Arrange the carbanions,

\dpi{100} \left ( CH_{3} \right )_{3}\bar{C},\bar{C}Cl_{3},\left ( CH_{3} \right )_{2}\bar{C}H,C_{6}H_{5}\bar{C}H_{2}

in order of their decreasing stability

  • Option 1)

    \dpi{100} C_{6}H_{5}\bar{C}H_{2}>\bar{C}Cl_{3}> \left ( CH_{3} \right )_{3}\bar{C}> \left ( CH_{3} \right )_{2}\bar{C}H

  • Option 2)

    \left ( CH_{3} \right )_{2}\bar{C}H>\bar{C}Cl_{3}> C_{6}H_{5}\bar{C}H_{2}> \left ( CH_{3} \right )_{3}\bar{C}

  • Option 3)

    \bar{C}Cl_{3}> C_{6}H_{5}\bar{C}H_{2}>\left ( CH_{3} \right )_{2}\bar{C}H> \left ( CH_{3} \right )_{3}\bar{C}

  • Option 4)

    \left ( CH_{3} \right )_{3}\bar{C}> \left ( CH_{3} \right )_{2}\bar{C}H> C_{6}H_{5}\bar{C}H_{2}>\bar{C}Cl_{3}

 

Answers (2)

As we learnt in 

Stability of Carbanions due to resonance -

More the no of resonating structure, more is the stability.

- wherein

 

 The order of stability of carbanion is -

\bar{C}Cl_{3}> C_{6}H_{5}\bar{C}H_{2}> (CH_{3})_{2}\bar{C}H> \left ( CH_{3} \right )_{3}\bar{C}


Option 1)

\dpi{100} C_{6}H_{5}\bar{C}H_{2}>\bar{C}Cl_{3}> \left ( CH_{3} \right )_{3}\bar{C}> \left ( CH_{3} \right )_{2}\bar{C}H

This option is incorrect

Option 2)

\left ( CH_{3} \right )_{2}\bar{C}H>\bar{C}Cl_{3}> C_{6}H_{5}\bar{C}H_{2}> \left ( CH_{3} \right )_{3}\bar{C}

This option is incorrect

Option 3)

\bar{C}Cl_{3}> C_{6}H_{5}\bar{C}H_{2}>\left ( CH_{3} \right )_{2}\bar{C}H> \left ( CH_{3} \right )_{3}\bar{C}

This option is correct

Option 4)

\left ( CH_{3} \right )_{3}\bar{C}> \left ( CH_{3} \right )_{2}\bar{C}H> C_{6}H_{5}\bar{C}H_{2}>\bar{C}Cl_{3}

This option is incorrect

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