Q&A - Ask Doubts and Get Answers
Q

Please,please help me Temperature at which r.m.s. speed of O2 is equal to that of neon at 300 K is :

Temperature at which r.m.s. speed of O2 is equal to that of neon at 300 K  is :

  • Option 1)

    280 K

  • Option 2)

    480 K

  • Option 3)

    680 K

  • Option 4)

    180 K

 
Answers (1)
260 Views

As we learnt in 

Rms speed of gas molecules -

Vrms=\sqrt{(3RT/M)}

- wherein

M- Molecular Mass , R- Gas Constant , T- Temperature

 

\frac{u_{1}}{u_{2}}= \sqrt{\frac{T_{1}\times M_{2}}{T_{2} M_{1}}},\: \: T_{1}= 480 K


Option 1)

280 K

Incorrect

Option 2)

480 K

Correct

Option 3)

680 K

Incorrect

Option 4)

180 K

Incorrect

Exams
Articles
Questions