The actinoids exhibit more number of oxidation states in general than the lanthanoids. This is because

  • Option 1)

    the 5f orbitals extend further from the nucleus than the 4f orbitals

  • Option 2)

    the 5f orbitals are more buried than the 4f orbitals

  • Option 3)

    there is a similarity between 4f and  5f orbitals in their angular part of the wave function

  • Option 4)

    the actinoids are more reactive than the lanthanoids.

 

Answers (1)

As we learnt in

Oxidation states -

The common oxidation state of lanthanoid is +3 low occasionally +2  and  +4  ions in solution or in the solid compound are also obtained.

-

 

 and

Oxidation states -

Ac shows +3 oxidation state generally but some Ac also, stable till +7 oxidation states.

-

 

Actinoids exhibits more number of exidation states in general than the Lanthanoids. This is because the 5f orbitals extended farther from the nucleus than the 4f orbitals. 


Option 1)

the 5f orbitals extend further from the nucleus than the 4f orbitals

This option is correct

Option 2)

the 5f orbitals are more buried than the 4f orbitals

This option is incorrect

Option 3)

there is a similarity between 4f and  5f orbitals in their angular part of the wave function

This option is incorrect

Option 4)

the actinoids are more reactive than the lanthanoids.

This option is incorrect

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