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The actinoids exhibit more number of oxidation states in general than the lanthanoids. This is because

• Option 1)

the $5f$ orbitals extend further from the nucleus than the $4f$ orbitals

• Option 2)

the $5f$ orbitals are more buried than the $4f$ orbitals

• Option 3)

there is a similarity between $4f$ and  $5f$ orbitals in their angular part of the wave function

• Option 4)

the actinoids are more reactive than the lanthanoids.

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As we learnt in

Oxidation states -

The common oxidation state of lanthanoid is +3 low occasionally +2  and  +4  ions in solution or in the solid compound are also obtained.

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and

Oxidation states -

Ac shows +3 oxidation state generally but some Ac also, stable till +7 oxidation states.

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Actinoids exhibits more number of exidation states in general than the Lanthanoids. This is because the 5f orbitals extended farther from the nucleus than the 4f orbitals.

Option 1)

the $5f$ orbitals extend further from the nucleus than the $4f$ orbitals

This option is correct

Option 2)

the $5f$ orbitals are more buried than the $4f$ orbitals

This option is incorrect

Option 3)

there is a similarity between $4f$ and  $5f$ orbitals in their angular part of the wave function

This option is incorrect

Option 4)

the actinoids are more reactive than the lanthanoids.

This option is incorrect

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