The electrons are more likely to be found: 

  • Option 1)

    in the region a and c

  • Option 2)

    in the region a and b 

  • Option 3)

    only in the region a 

  • Option 4)

    only in the region c

Answers (1)

 

The energy (E) of a quantum of radiation -

E=hv

Where h is plank’s constant and \nu is frequency

-

 

 

Bohr's model -

1. Force of attraction between the nucleus and an electron is equal to centripetal force.

2. mvr=\frac{nh}{2\pi }

    n = principal quantum number.

3. Energy can be absorbed or emitted when electron transfer orbit  E_{1}-E{_{2}}=h\nu

-

 

We knew that probability of finding an electron is proportional \left ( \psi \right )^{2}r.

Now on converting this graph of \psi \left ( x \right )x into \left ( \psi \left ( x \right ) \right )^{2}vs\: \: \: x, we will get maxima at point \left ( a \right ) & \left ( c \right ).

Therefore, the probability of finding an electron is maximum at \left ( a \right ) & \left ( c \right ).


Option 1)

in the region a and c

Option 2)

in the region a and b 

Option 3)

only in the region a 

Option 4)

only in the region c

Preparation Products

Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Test Series JEE Main April 2021

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 6999/- ₹ 4999/-
Buy Now
JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Test Series JEE Main April 2022

Take chapter-wise, subject-wise and Complete syllabus mock tests and get an in-depth analysis of your test..

₹ 6999/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
 
Exams
Articles
Questions