Get Answers to all your Questions

header-bg qa

The total energy of a particle, executing simple harmonic motion is

  • Option 1)

    \alpha \; x

    where x is the displacement from the mean position.

  • Option 2)

    \alpha \, \, x^{2}

     

    where x is the displacement from the mean position.

  • Option 3)

    independent of  x

    where x is the displacement from the mean position.

  • Option 4)

    \alpha \, \, x^{1/2}

    where x is the displacement from the mean position.

 

Answers (1)

best_answer

Under simple harmonic motion, total energy

=\frac{1}{2}ma^{2}\omega ^{2}

Total energy is independent of x.

Total energy of s.u.w =\frac{1}{2}mw^{2}A^{2}

i.e total energy is indepedent of x


Option 1)

\alpha \; x

where x is the displacement from the mean position.

Incorrect option

Option 2)

\alpha \, \, x^{2}

 

where x is the displacement from the mean position.

Incorrect option

Option 3)

independent of  x

where x is the displacement from the mean position.

Correct option

Option 4)

\alpha \, \, x^{1/2}

where x is the displacement from the mean position.

Incorrect option

Posted by

Aadil

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE