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Total number of four digit odd numbers that can be formed using 0, 1, 2, 3, 5, 7 are

  • Option 1)

    216

  • Option 2)

    375

  • Option 3)

    400

  • Option 4)

    720

 

Answers (1)

best_answer

As we learnt in

Number of Permutations with repetition -

The number of ways of filling r places where each place can be filled by any one of  n objects.

It is n^{r}

- wherein

Where r\geq 0

 

 

Number of Permutations without repetition -

Arrange n objects taken r at a time equivalent to filling r places from n things.

 

- wherein

Where r\leq n\ \; and\; \; r\geq 0

 

 We have 0, 1, 2, 3, 5, 7 and Repetition is allowed.

Correct option is 4.

 

 


Option 1)

216

This is an incorrect option.

Option 2)

375

This is an incorrect option.

Option 3)

400

This is an incorrect option.

Option 4)

720

This is the correct option.

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Plabita

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