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What is the conductivity of a semiconductor sample having electron concentration of 5×1018 m−3, hole concentration of 5×1019 m−3, electron mobility of 2.0 m2 V−1 s−1 and hole mobility of 0.01 m2 V−1 s−1 ?

(Take charge of electron as 1.6×10−19 C)

  • Option 1)

    1.68 (\Omega - m)−1

  • Option 2)

     1.83 (\Omega - m)−1

  • Option 3)

    0.59 (\Omega - m)−1

  • Option 4)

    1.20 (\Omega - m)−1

     

 

Answers (1)

best_answer

As we learnt in

Electrical Conductivity (σ) -

\sigma =e \left (n_{e}\mu _{e}+n_{\lambda}\mu _{h} \right )
 

- wherein

n_{e}= electron \: density

n_{h}= hole \: density

\mu _{e}= mobility \: of \: electron

\mu _{h}= mobility \: of \: holes

 

 Conductivity \sigma=e \left(n_{e}\mu_{e}+n_{h}\mu_{h} \right )

=1.6\times 10^-{19} \left({5\times 10^{18}}\times2+5\times10^{19}\times 0.1 \right )

=1.6\times 10^-{19} \left(10^{19}+0.5\times 10^{19} \right )

=1.6\times 1.05=1.680 (\omega-m)^{-1}

Corect option is 1.

 


Option 1)

1.68 (\Omega - m)−1

This the correct option.

Option 2)

 1.83 (\Omega - m)−1

This is an incorrect option.

Option 3)

0.59 (\Omega - m)−1

This is an incorrect option.

Option 4)

1.20 (\Omega - m)−1

 

This is an incorrect option.

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Aadil

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