When we move a charge of 20 coulombs by a distance of 2 cm, then 2 Joule of work is done. What is the potential difference between the initial and final position of charge?

  • Option 1)

    4 V

  • Option 2)

    0.6 V

  • Option 3)

    0.1 V

  • Option 4)

    8 V

 

Answers (1)

As we learnt in

Electric Potential -

V=\frac{w}{q_{0}}

- wherein

w - work done 

q0 - unit charge.

 

 \Delta V = \frac{\Delta w}{q} = \frac{2J}{20C} = 0.1 \ V


Option 1)

4 V

This option is incorrect

Option 2)

0.6 V

This option is incorrect

Option 3)

0.1 V

This option is correct

Option 4)

8 V

This option is incorrect

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