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Points \mathrm{A\,\&\, B } are in the first quadrant; point 'O' is the origin . If the slope of OA is 1 , slope of OB is 7 and \mathrm{\mathrm{OA}=\mathrm{OB} }, then the slope of \mathrm{\mathrm{AB} } is:

Option: 1

-1 / 5


Option: 2

-1 / 4


Option: 3

-1 / 3


Option: 4

-1 / 2


Answers (1)

best_answer

\tan \theta=7 ; \mathrm{OA}=\mathrm{OB}=\mathrm{r} \quad \sin \theta=\frac{7}{5 \sqrt{2}} \quad \cos \theta=\frac{1}{5 \sqrt{2}}
\text { now } \mathrm{m}_{\mathrm{AB}}=\frac{-1}{2} \quad

Posted by

Deependra Verma

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