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Potential difference between the points P and Q in the electric circuit shown is

 

Option: 1

4.5 V


Option: 2

1.2 V


Option: 3

2.4 V


Option: 4

2.88 V


Answers (1)

best_answer

Equivalent resistance between P and Q

\frac{1}{R_{P Q}}=\frac{1}{(6+2)}+\frac{1}{3}+\frac{1}{(4+12)} \Rightarrow R_{P Q}=\frac{48}{25} \Omega

Current between P and Q ; i=1.5 \mathrm{~A}

So, potential difference between P and Q

V_{P Q}=1.5 \times \frac{48}{25}=2.88 \mathrm{~V}

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seema garhwal

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