Find the value of pushing force P just to move the block. If the coeffecient of friction between block and the floor is given as \mu = 0.6.

Answers (1)

Minimum Force to avoid sliding of body down on an inclined plane -

   

 


 

P=W \left[\frac{sin(\lambda-\theta)}{cos(\theta+\lambda)} \right ]

P = Pulling force 

\lambda= Angle of Inclination

\theta= Angle of friction

- wherein

For equilibrium 

R+P sin\alpha=W cos\lambda

P cos \alpha+F=W sin \lambda

Use F=\mu R

 

3 + mg sin \theta = P + \mu mg cos \theta

3 + \frac{100}{\sqrt{2}} = P + 0.6 \times \frac{100}{\sqrt{2}}

P = 32 N

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