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[\mathrm{A}] \rightarrow[\mathrm{B}]
Reactant Product
If formation of compound [B] follows the first order of kinetics and after 70 minutes the concentration of [\mathrm{A}] was found to be half of its initial concentration. Then the rate constant of the reaction is \mathrm{x \times 10^{-6} \mathrm{~s}^{-1}}. The value of \mathrm{x} is____________. (Nearest Integer)

Option: 1

165


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

we know for the first order reaction,

\mathrm{Half\: life\: t_{1/2}=\frac{\ln 2}{k}}
\mathrm{70\: min=\frac{\ln 2}{x\times 10^{-6}}\, sec}
\mathrm{70 \times 60 =\frac{\ln 2}{x \times 10^{-6}}}
\mathrm{x= 165}

Ans=165.

Posted by

Nehul

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