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Reaction of an inorganic sulphite X with dilute H_{2}SO_{4} generates compound Y.Reaction of Y with \mathrm{NaOH} gives X. Further, the reaction of X with Y and water affords compound Z. Y and Z, respectively, are :
Option: 1 SO_{2}\; \; and \; \; Na_{2}SO_{3}
Option: 2 SO_{3}\; \; and \; \; NaHSO_{3}
Option: 3 SO_{2}\; \; and \; \; NaHSO_{3}
Option: 4 S\; \; and \; \; Na_{2}SO_{3}

Answers (1)

best_answer

The reaction will be-

 

So, Y and Z, respectively, are SO_{2}\; \; and \; \; NaHSO_{3}

Therefore, the correct option is (3).

Posted by

Kuldeep Maurya

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