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  • Resistances are connected in a meter bridge circuit as shown in the figure. The balancing length <img alt="\mathrm{l_{1}\; is \; 40 \mathrm{~cm}.}" src="/latex-image/?%5Cmathrm%7Bl_%7B1%7D%5C%3B%20

Resistances are connected in a meter bridge circuit as shown in the figure. The balancing length \mathrm{l_{1}\; is \; 40 \mathrm{~cm}.} Now an unknown resistance \mathrm{x} is connected in series with \mathrm{\mathrm{P}} and new balancing length is found to be \mathrm{80 \mathrm{~cm}} measured from the same end. Then the value of \mathrm{x} will be ___________ \mathrm{\Omega .}

Option: 1

20


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

Initial

\frac{P}{Q}=\frac{l_{1}}{100-l_{1}=\frac{4}{6}}\rightarrow (1)

Final

\mathrm{\frac{P+x}{Q}=\frac{l_{2}}{100-l_{2}}=\frac{4}{1}}\rightarrow (2)

\mathrm{\frac{P}{p+x}=\frac{4/6}{4/1}=\frac{1}{6}}

\mathrm{6P=P+x}

\mathrm{5P=x}

\mathrm{x=5p=20\Omega }

The value of x will be \mathrm{20\Omega }

Posted by

Gaurav

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