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  • Silver and copper voltameter are connected in parallel with a battery of e.m.f. . In 30 mi

Silver and copper voltameter are connected in parallel with a battery of e.m.f. 12 \mathrm{~V}. In 30 minutes, 1 \mathrm{~g} of silver and 1.8 \mathrm{~g} of copper are liberated. The power supplied by the battery is

\mathrm{\left(Z_{C u}=6.6 \times 10^{-4} \mathrm{~g} / \mathrm{C}\right. and \left.Z_{A g}=11.2 \times 10^{-4} \mathrm{~g} / \mathrm{C}\right) }

 

Option: 1

24.13 \mathrm{~J} / \mathrm{sec}


Option: 2

2.413 \mathrm{~J} / \mathrm{sec}


Option: 3

0.2413 \mathrm{~J} / \mathrm{sec}


Option: 4

2413 \mathrm{~J} / \mathrm{sec}


Answers (1)

The current taken by the silver voltameter

\mathrm{I_1=\frac{n}{Z t}=\frac{1}{11.2 \times 10^{-4} \times 30 \times 60}=0.496 \mathrm{~A} }

and by copper voltameter

\mathrm{I_2=\frac{1.8}{6.6 \times 10^{-4} \times 30 \times 60}=1.515 \mathrm{~A} }

The current \mathrm{I=\left(I_1+I_2\right)=2.011 \mathrm{~A}}

\mathrm{Power ~P=I V=2.011 \times 12=24.132 \mathrm{~J} / \mathrm{sec}}

Posted by

Kshitij

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