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Simplified adsorption spectrum of there  complexed \left (i) , (ii) and (iii)\right of , M^{nt} ion are provided below ; their \lambda_{max} values are marked as A,B and C respectively. The correct match between the complexed and their \lambda_{max} value is :  \left [ M\left ( NCS \right )_{6} \right ]^{\left ( -6+n \right )} \left [ MF_{6} \right ]^{\left ( -6+n \right )} \left [ M \left ( NH _{3}\right )_{6}\right ]^{n+}
Option: 1 A-ii , B-i , C-iii
Option: 2 A-ii , B-iii , C-i
Option: 3 A-i , B-ii , C-iii
Option: 4 A-iii , B-i , C-ii

Answers (1)

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(i) [M(NCS)](-6+n): NCS is a medium filed ligand. Thus, splitting will be required medium amount of energy. Thus \lambda_{max} will be medium.
(ii) [MF6](-6+n): F is a  weak field ligand. Thus, splitting will be low and low energy will be required. Thus, \lambda_{max} will be highest.

(iii) [M(NH3)]n+: NH3 is strong filed ligand. Thus, splitting will be high and high energy will be required. Thus, \lambda_{max} will be lower.

Thus, the correct sequence is:

A-(iii), B-(i), C-(ii)

Therefore, Option(4) is correct.

Posted by

Kuldeep Maurya

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