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Sodium nitroprusside, when added to an alkaline solution of sulphide ions, produces purple colour ion due to the formation of

Option: 1

\mathrm{Na}\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NOS}\right]


Option: 2

\mathrm{Na}_{2}\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NOS}\right]


Option: 3

\mathrm{Na}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{5} \mathrm{NOS}\right]


Option: 4

\mathrm{Na}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{5} \mathrm{NOS}\right]


Answers (1)

best_answer

As we have learnt, 

Sulphide ions are detected in solution by adding Sodium Nitroprusside solution. A Violet coloration confirms the presence of Sulphide ions in solution

\underset{\text{Sodium nitroprusside}}{\mathrm{Na}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{5} \mathrm{NO}\right]}+\mathrm{S}^{2-} \longrightarrow \underset{\substack{\text { Sodium thio-nitroprusside } \\ \text { (violet) }}}{\mathrm{Na}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{5} \mathrm{NOS}\right]}

Hence, the correct answer is Option (4)

Posted by

Devendra Khairwa

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