A copper rod moves with a constant angular velocity ω, about a long straight wire carrying a current i. If the ends of the rod from the wire are at distances a and b, then the e.m.f. induced in the rod is

  • Option 1)

    \frac{\mu 0i\left ( wa \right )}{2\pi} In\frac{b}{a}

  • Option 2)

    \frac{\mu 0i\left ( wb \right )}{2\pi} In\frac{b}{a}

  • Option 3)

    zero

  • Option 4)

    \frac{\mu 0iw\left ( a+b\right )}{2\pi} In\frac{b}{a}

 

Answers (1)

 

Motional EMF -

\varepsilon = Blv
 

- wherein

B\rightarrow magnetic field

l\rightarrow length

u\rightarrow velocity of u perpendicular to uniform magnetic field.

 

 The velocity of any element and field applied by current carrying wire are parallel. Hence Emf induced is Zero.


Option 1)

\frac{\mu 0i\left ( wa \right )}{2\pi} In\frac{b}{a}

Option is incorrect

Option 2)

\frac{\mu 0i\left ( wb \right )}{2\pi} In\frac{b}{a}

Option is incorrect

Option 3)

zero

Option is correct

Option 4)

\frac{\mu 0iw\left ( a+b\right )}{2\pi} In\frac{b}{a}

Option is incorrect

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