An e.m.f. of 5 millivolt is induced in a coil when in a nearby placed another coil, the current changes by 5 ampere in 0.1 second. The coefficient of mutual induction between the two coils will be :

  • Option 1)

    1 Henry

  • Option 2)

      0.1 Henry

  • Option 3)

    0.1 millihenry

  • Option 4)

     0.01 millihenry

 

Answers (6)

 

According to Faraday's Second Law -

\varepsilon _{2}= -N_{2}\frac{d\phi_{2}}{dt}= -M\frac{dI_{1}}{dt}

-

 

 \varepsilon = M\cdot \frac{dI}{dt}\Rightarrow 5mv = M\times \left ( \frac{5}{0.1} \right )

M=0.1mH


Option 1)

1 Henry

This solution is incorrect

Option 2)

  0.1 Henry

This solution is incorrect

Option 3)

0.1 millihenry

This solution is correct

Option 4)

 0.01 millihenry

This solution is incorrect

D Daniel

3

 

D Daniel

3

0.1mh

 

Option 3) 0.1 millihenry

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