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An e.m.f. of 5 millivolt is induced in a coil when in a nearby placed another coil, the current changes by 5 ampere in 0.1 second. The coefficient of mutual induction between the two coils will be :

  • Option 1)

    1 Henry

  • Option 2)

      0.1 Henry

  • Option 3)

    0.1 millihenry

  • Option 4)

     0.01 millihenry

 

Answers (6)

best_answer

 

According to Faraday's Second Law -

\varepsilon _{2}= -N_{2}\frac{d\phi_{2}}{dt}= -M\frac{dI_{1}}{dt}

-

 

 \varepsilon = M\cdot \frac{dI}{dt}\Rightarrow 5mv = M\times \left ( \frac{5}{0.1} \right )

M=0.1mH


Option 1)

1 Henry

This solution is incorrect

Option 2)

  0.1 Henry

This solution is incorrect

Option 3)

0.1 millihenry

This solution is correct

Option 4)

 0.01 millihenry

This solution is incorrect

Posted by

divya.saini

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3

 

Posted by

Daniel

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3

Posted by

Daniel

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3

Posted by

Kunche vinod

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0.1mh

 

Posted by

Prerna sakharkar

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Option 3) 0.1 millihenry

Posted by

Rwirup Narzary

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