Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Solve! Beats are produced with the help of two sound waves of amiplitudes 3 and 5 units. The ratio of maximum to minimum intensity in the beats is

Beats are produced with the help of two sound waves of amiplitudes 3 and 5 units. The ratio of maximum to minimum intensity in the beats is 

  • Option 1)

    2:1

  • Option 2)

    5:3

  • Option 3)

    4:1

  • Option 4)

    16:1

 

Answers (1)

best_answer

\frac{I_{max}}{I_{min}}= \left ( \frac{a_{1}+a_{2}}{a_{1}-a_{2}} \right )^{2} = \left ( \frac{5+3}{5-3} \right )^{2}= 16/1

 

Superposition of sinusoidal wave -

y_{1}= A\sin \left ( kx-\omega t \right )\\y_{2}= A\sin \left ( kx-\omega t +\phi \right )

 

- wherein

Resultant equation is y= 2A\cdot \cos \left ( \phi /2 \right )\cdot \sin \left ( kx-\omega t+\frac{\phi }{2} \right )

 

 


Option 1)

2:1

This is incorrect

Option 2)

5:3

This is incorrect

Option 3)

4:1

This is incorrect

Option 4)

16:1

This is correct

Posted by

divya.saini

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

Is it difficult to get into NIT Durgapur? JEE Main cut-offs for BTech programmes
anam-khan

JEE Main Deleted Syllabus 2025: Topics to skip this year; why no optional questions?
anam-khan

NTA Exam 2025 Live: UGC NET admit card out for all exams; JEE Main session 1 hall ticket soon

Latest Question