# Calculate the molality of a solution containing of Acetic acid in Ethanol if the mass of solute =  10g and the density of Ethanol = 0.789 gmL-1. Option 1) 0.2112 Option 2) 0.2012 Option 3) 0.1992 Option 4) 0.2002

As we have learnt

Molality -

Molality (m) = (number of moles of solute)/(mass of solvent in kg)

- wherein

It is defined as the number of moles of solute present in 1 kg of solvent. It is denoted by m.

Mass of solute $= \frac{10}{60} = \frac{1}{6}$

Volume of ethanal = 1 L

Weight of ethanal = 1000 x 0.789 = 789g

$Molality = \frac{mass\;of\;solute}{mass\;of\;solution} = \frac{10}{60\times\frac{789}{1000}} = 0.2112m$

Option 1)

0.2112

Option 2)

0.2012

Option 3)

0.1992

Option 4)

0.2002

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