Calculate the molality of a solution containing of Acetic acid in Ethanol if the mass of solute = 10g and the density of Ethanol = 0.789 gmL-1.
As we have learnt
Molality (m) = (number of moles of solute)/(mass of solvent in kg)
It is defined as the number of moles of solute present in 1 kg of solvent. It is denoted by m.
Mass of solute
Volume of ethanal = 1 L
Weight of ethanal = 1000 x 0.789 = 789g
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