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  • Solve! - Complex numbers and quadratic equations - JEE Main-6

f\left ( x \right )= 2x^{2}+ax+2  if  f\left ( x \right )= 0  has no real root then 'a'  takes value lying in interval

  • Option 1)

    (-5,5)

  • Option 2)

    (-4,4)

  • Option 3)

    (-6,6)

  • Option 4)

    (-7,7)

 

Answers (1)

best_answer

\because f(x)=0  has no real root, so D< 0

\therefore a^{2}-16< 0\Rightarrow a\epsilon (-4,4)

\therefore  Option B

 

Quadratic Expression Graph when a > 0 & D < 0 -

No Real and Equal root of

f\left ( x \right )= ax^{2}+bx+c

& D= b^{2}-4ac

- wherein

 

 


Option 1)

(-5,5)

This is incorrect

Option 2)

(-4,4)

This is correct

Option 3)

(-6,6)

This is incorrect

Option 4)

(-7,7)

This is incorrect

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Plabita

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