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  • Solve! - Electromagnetic Induction and Alternating currents - JEE Main-2

In an AC generator, a coil with N turns, all of the same area A and total resistance R , rotates with frequency \omega in a magnetic field B . The maximum value of emf generated in the coil is

  • Option 1)

    NAB\omega

  • Option 2)

    NABR\omega

  • Option 3)

    NAB

  • Option 4)

    NABR

 

Answers (2)

As we learnt in 

Motional E.m.f due to rotational motion -

Semicircle conducting loop

\varepsilon = \frac{1}{2}Bwr^{2}

i = \frac{Bwr^{2}}{2R}

 

- wherein

Flux at any instant is\phi=BA\ cos\omega t

emf=(BA\;\omega sin \omega t)N

maximum emf=NBA \omega

 


 


Option 1)

NAB\omega

This option is correct

Option 2)

NABR\omega

This option is incorrect

Option 3)

NAB

This option is incorrect

Option 4)

NABR

This option is incorrect

Posted by

Sabhrant Ambastha

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NABOmega

Posted by

Sandhya

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