In the nuclear reaction given by 2He4 + 7N141H1 + X then the nucleus X is :

 

  • Option 1)

    Nitrogen of mass 16

     

  • Option 2)

     Nitrogen of mass 17

     

  • Option 3)

    Oxygen of mass 16

     

  • Option 4)

     Oxygen of mass 17

     

 

Answers (1)

As we discussed in concept

Binding energy -

B.E=\left [ Zm_{p}+(A-Z)m_{n}-M_{x} \right ]c^{2} 

amount of energy released when nucleons  come together to form a nuclei.

M_{x} = mass of nuclei formed

 

- wherein

m_{p}- mass\ of\ proton

m_{n}- mass\ of \ neutron

Z- atomic\ number

A- atomic\ mass

 

 

_{2}^{4}\textrm{He}+_{7}^{14}\textrm{N}\:\rightarrow _{1}^{1}\textrm{H}+_{Z}^{A}\textrm{X}

Balancing atomic Number we get

2+7 = 1+Z        =>    Z=8

Balancing mass number we get 4+14=A+1

=> A=17

\therefore the nucleus X is _{8}^{17}\textrm{O}


Option 1)

Nitrogen of mass 16

 

This option is incorrect.

Option 2)

 Nitrogen of mass 17

 

This option is incorrect.

Option 3)

Oxygen of mass 16

 

This option is incorrect.

Option 4)

 Oxygen of mass 17

 

This option is correct.

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