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  • Solve it, 20 L of SO2 diffuses through a porous partition in 60 seconds. Volume of O2 diffuse under similar conditions in 30 seconds will be :

 20 L  of SO2 diffuses through a porous partition in 60 seconds. Volume of O2 diffuse under similar conditions in 30 seconds will be :

  • Option 1)

    12.14 L

  • Option 2)

    14.14 L

  • Option 3)

    18.14 L

  • Option 4)

    28.14 L

 

Answers (1)

As we learnt in 

Graham’s law of diffusion -

\dpi{100} r_{1}/r_{2}=\sqrt{M_{1}/M_{2}}  where r is rate of diffusion of gas , M is molar mass.

-

\frac{20}{60}\times \frac{30}{V}= \sqrt{\frac{32}{64}}\Rightarrow V= 14.14\: l

 


Option 1)

12.14 L

Incorrect

Option 2)

14.14 L

Correct

Option 3)

18.14 L

Incorrect

Option 4)

28.14 L

Incorrect

Posted by

Vakul

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