#### A compound on analysis was found to have the following composition : (i) Sodium 14.31%, (ii) Sulphur 9.97%, (iii) Oxygen 69.5%, (iv) Hydrogen 6.22%. Calculate the molecular formula of the compund assuming that whole of Hydrogen in the compound is present as water of Crystallization. Molecular mass of compund is 322. Option 1) Na2SH20O10 Option 2) Na2SH20O14 Option 3) Na2SH20O7 Option 4) Na2SH30O16

As we have learnt

Molecular Formula -

The molecular formula shows the exact number of different types of atoms present in a molecule of a compound.

- wherein

For glucose, empirical formula is CH2O .its molar mass is 180 gram.

n = molar mass/empirical formula mass = 180/30=6

Hence molecular formula= C6H12O6

 Element %age Atomic mass Relative no of atoms Simplest Ratio Na 14.31 23 0.622 S 9.97 32 0.311 H 6.22 1 6.22 O 69.50 16 4.34

Empirical formula = Na2SH20O14

Empirical formula mass

Molecular mass = 322

Molecular Formula = Na2SH20O14

Option 1)

Na2SH20O10

Option 2)

Na2SH20O14

Option 3)

Na2SH20O7

Option 4)

Na2SH30O16