If radius of the _{13}^{27}Al nucleus is estimated to be 3.6 fermi then the radius of _{52}^{125}Al nucleus be nearly

  • Option 1)

    4\: fermi

  • Option 2)

    5\: fermi

  • Option 3)

    6\: fermi

  • Option 4)

    8\: fermi

 

Answers (1)

As we learnt in

Binding energy per nucleon -

 

- wherein

This graph shows the stability of nuclei many nuclear phenomena can be explained by this graph

 

 R=R_{0}A^{1/3}

\frac{R_{2}}{R_{1}}=\left(\frac{A_{2}}{A_{1}} \right )^{1/3}= \left(\frac{125}{27} \right )^{1/3}=\frac{5}{3}

R_{2}=\frac{5}{3}\times3.6\ fm

R_{2}=6\ fm

Correct option is 3.


Option 1)

4\: fermi

This is an incorrect option.

Option 2)

5\: fermi

This is an incorrect option.

Option 3)

6\: fermi

This is the correct option.

Option 4)

8\: fermi

This is an incorrect option.

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