Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

The tangent to the parabola y^{2}=4xat the point where it intersects the circle x^{2}+y^{2}=5 in the first quadrant, passes through the point :

  • Option 1)

    \left ( -\frac{1}{3},\frac{4}{3} \right )

  • Option 2)

    \left ( \frac{1}{4},\frac{3}{4} \right )

  • Option 3)

    \left ( \frac{3}{4},\frac{7}{4} \right )

  • Option 4)

    \left ( -\frac{1}{4},\frac{1}{2} \right )

 

Answers (1)

best_answer

Point of intersection of y^{2}=4x and x^{2}+y^{2}=5 is (1,2) and (1,-2)

Equation of tangent at (1, 2)

 2y=2(x+1)\Rightarrow y=x+1

y-x=1    point \left ( \frac{3}{4} , \frac{7}{4}\right ) satisfies .

 


Option 1)

\left ( -\frac{1}{3},\frac{4}{3} \right )

Option 2)

\left ( \frac{1}{4},\frac{3}{4} \right )

Option 3)

\left ( \frac{3}{4},\frac{7}{4} \right )

Option 4)

\left ( -\frac{1}{4},\frac{1}{2} \right )

Posted by

solutionqc

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JAC Chandigarh Counselling 2025: Round 1 seat allotment result out for BTech admissions
anam-khan

JoSAA round 5 seat allotment result 2025 out on josaa.nic.in
anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today

Latest Question