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Photon of frequency \upsilon has a momentum associated with it. If c is the velocity of light, the momentum is

Option 1)

h\upsilon /c\;

Option 2)

\; \upsilon /c\;

Option 3)

\; h\upsilon c\;

Option 4)

\; h\upsilon /c^{2}

Answers (1)

best_answer

As we learnt in

Momentum of photon -

\fn_jvn P = \frac{E}{C}= \frac{h}{\lambda }

- wherein

P-Momentum

h- Plank's\ Constant

C- Speed\ of \ light

E - Energy

\lambda-Wavelength

 

 Wavelength \lambda=\frac{c}{\nu}

Therefore Momentum p=\frac{h}{\lambda}=\frac{h}{\left(\frac{c}{\nu} \right )}

p=\frac{h\nu}{c}

Correct option is 1.


Option 1)

h\upsilon /c\;

This is the correct option.

Option 2)

\; \upsilon /c\;

This is an incorrect option.

Option 3)

\; h\upsilon c\;

This is an incorrect option.

Option 4)

\; h\upsilon /c^{2}

This is an incorrect option.

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