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The figure shows a square loop L of side 5 cm which is connected to a network of resistances. The whole setup is moving towards right with a constant speed of $1 cm$ $s^{-1}$ . At some instant, a part of L is in a uniform magnetic field of 1 T, perpendicular to the plane of the loop. If the resistance of L is $1.7\Omega$ , the current in the loop at that instant will be close to :

Option 1)
$150 \mu A$

Option 2)
$115 \mu A$

Option 3)
$60 \mu A$

Option 4)
$170 \mu A$

Answers (1)

best_answer

Motional EMF -

$\varepsilon = Blv$

- wherein

$B\rightarrow$ magnetic field

$l\rightarrow$ length

$u\rightarrow$ velocity of u perpendicular to uniform magnetic field.

$B=1T$

$L=5\times10^{-2}m$

$v=1\times10^{-2}m/s$

$E=BVL=5\times10^{-4}V$

The circuit ABCD is a wheat stone bridge circuit

$\Rightarrow Req=\frac{4\times2}{4+2}=\frac{4}{3}\Omega$

It is given the resistance of square = $1.7\Omega$

R total = $\frac{4}{3}+1.7\Omega$

$I=\frac{V}{R}=\frac{5\times10^{-4}}{\frac{4}{3}+1.7}=170 \mu A$

Option 1)

$150 \mu A$

Option 2)

$115 \mu A$

Option 3)

$60 \mu A$

Option 4)

$170 \mu A$

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