# The figure shows a square loop L of side 5 cm which is connected to a network of resistances. The whole setup is moving towards right with a constant speed of $1 cm$ $s^{-1}$. At some instant, a part of L is in a uniform magnetic field of 1 T, perpendicular to the plane of the loop. If the resistance of L is $1.7\Omega$, the current in the loop at that instant will be close to : Option 1) $150 \mu A$ Option 2) $115 \mu A$ Option 3) $60 \mu A$ Option 4) $170 \mu A$

Motional EMF -

$\varepsilon = Blv$

- wherein

$B\rightarrow$ magnetic field

$l\rightarrow$ length

$u\rightarrow$ velocity of u perpendicular to uniform magnetic field.

$B=1T$

$L=5\times10^{-2}m$

$v=1\times10^{-2}m/s$

$E=BVL=5\times10^{-4}V$

The circuit ABCD is a wheat stone bridge circuit

$\Rightarrow Req=\frac{4\times2}{4+2}=\frac{4}{3}\Omega$

It is given the resistance of square = $1.7\Omega$

R total =$\frac{4}{3}+1.7\Omega$

$I=\frac{V}{R}=\frac{5\times10^{-4}}{\frac{4}{3}+1.7}=170 \mu A$

Option 1)

$150 \mu A$

Option 2)

$115 \mu A$

Option 3)

$60 \mu A$

Option 4)

$170 \mu A$

### Preparation Products

##### Knockout JEE Main July 2020

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 12999/- ₹ 6999/-
##### Rank Booster JEE Main 2020

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 9999/- ₹ 4999/-
##### Test Series JEE Main July 2020

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 4999/- ₹ 1999/-
##### Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 17999/- ₹ 11999/-