Get Answers to all your Questions

header-bg qa

Figure shows a network of capacitors where the numbers indicates capacitances in micro Farad.  The value of capacitance C if the equivalent capacitance between point A and B is to be 1 µF is :

  • Option 1)

    \frac{31}{23}\, \mu F

  • Option 2)

    \frac{32}{23}\, \mu F

  • Option 3)

    \frac{33}{23}\, \mu F

  • Option 4)

    \frac{34}{23}\, \mu F

 

Answers (2)

best_answer

As we learnt in

Series Grouping -

\frac{1}{C_{eq}}=\frac{1}{C_{1}}+\frac{1}{C_{2}}+\cdots

- wherein

 

 

Parallel Grouping -

C_{eq}=C_{1}+C_{2}+\cdots

- wherein

 

 C_{AB} = 1 \mu f = \frac{C \times \frac{32}{9}}{C+\frac{32}{9}}=\frac{\frac{32C}{9}}{\frac{32}{9}+C}

\frac{32C}{9}=\frac{32}{9} + C

\Rightarrow C=\frac{32}{23}\mu F

 

 


Option 1)

\frac{31}{23}\, \mu F

Incorrect

Option 2)

\frac{32}{23}\, \mu F

Correct

Option 3)

\frac{33}{23}\, \mu F

Incorrect

Option 4)

\frac{34}{23}\, \mu F

Incorrect

Posted by

Plabita

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE