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For 0.1 M solution, the colligative property will follow the order

  • Option 1)

    NaCl > Na_{2}SO_{4} > Na_{3}PO_{4}

     

     

     

  • Option 2)

    NaCl< Na_{2}SO_{4} < Na_{3}PO_{4}

  • Option 3)

    NaCl > Na_{2}SO_{4} \approx Na_{3}PO_{4}

  • Option 4)

    NaCl< Na_{2}SO_{4} = Na_{3}PO_{4}

 

Answers (1)

best_answer

As we learned

 

Types of colligative properties -

Four types of colligative properties;

(a)    Relative lowering of vapour pressure.

(b)    Elevation in boiling point.

(c)    Depression in freezing point

(d)    Osmotic pressure.

 

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Colligative property in decreasing order

Na _{3}PO_{4} > Na _{2}SO_{4} > NaCl

Na _{3}PO_{4} \rightarrow 3Na^{+}+PO_{4}^{3-}=4

Na _{2}SO_{4} \rightarrow 2Na^{+}+SO_{4}^{2-}=3

NaCl \rightarrow Na^{+}+Cl^{-}=2

 


Option 1)

NaCl > Na_{2}SO_{4} > Na_{3}PO_{4}

 

 

 

Option 2)

NaCl< Na_{2}SO_{4} < Na_{3}PO_{4}

Option 3)

NaCl > Na_{2}SO_{4} \approx Na_{3}PO_{4}

Option 4)

NaCl< Na_{2}SO_{4} = Na_{3}PO_{4}

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