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# Solve it, For 0.1 M solution, the colligative property will follow the order

For 0.1 M solution, the colligative property will follow the order

• Option 1)

$NaCl > Na_{2}SO_{4} > Na_{3}PO_{4}$

• Option 2)

$NaCl< Na_{2}SO_{4} < Na_{3}PO_{4}$

• Option 3)

$NaCl > Na_{2}SO_{4} \approx Na_{3}PO_{4}$

• Option 4)

$NaCl< Na_{2}SO_{4} = Na_{3}PO_{4}$

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As we learned

Types of colligative properties -

Four types of colligative properties;

(a)    Relative lowering of vapour pressure.

(b)    Elevation in boiling point.

(c)    Depression in freezing point

(d)    Osmotic pressure.

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Colligative property in decreasing order

$Na _{3}PO_{4} > Na _{2}SO_{4} > NaCl$

$Na _{3}PO_{4} \rightarrow 3Na^{+}+PO_{4}^{3-}=4$

$Na _{2}SO_{4} \rightarrow 2Na^{+}+SO_{4}^{2-}=3$

$NaCl \rightarrow Na^{+}+Cl^{-}=2$

Option 1)

$NaCl > Na_{2}SO_{4} > Na_{3}PO_{4}$

Option 2)

$NaCl< Na_{2}SO_{4} < Na_{3}PO_{4}$

Option 3)

$NaCl > Na_{2}SO_{4} \approx Na_{3}PO_{4}$

Option 4)

$NaCl< Na_{2}SO_{4} = Na_{3}PO_{4}$

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