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If R = universal gas constant, the amount of heat needed to raise the temperature of 2 mole of an ideal monoatomic gas from 273K to 373K when no work is done

  • Option 1)

    100R

  • Option 2)

    200R

  • Option 3)

    300R

  • Option 4)

    150R

 

Answers (1)

best_answer

As we learnt in 

Work done in isochoric process -

W = 0
 

- wherein

\because W= \int P\, dV

since dv= 0

W = 0

 

 and

 

Total internal energy -

U= U_{K}+U_{P}
 

- wherein

Change in internal energy

\Delta U= n\frac{f}{2}R\Delta T

(Always)

f is degree of freedom

 

 When no work is done. 

Q= \Delta U=nC_{v}\Delta T

= 2 \times (\frac{3R}{2})\times 100=300R

 

 


Option 1)

100R

Incorrect

Option 2)

200R

Incorrect

Option 3)

300R

correct

Option 4)

150R

Incorrect

Posted by

Aadil

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