On moving a charge of 20 coulomb by 2 cm, 2 J of work is done, then the potential difference between the points is

 

  • Option 1)

    0.1\: V

  • Option 2)

    8\: V

  • Option 3)

    2\: V

  • Option 4)

    0.5\: V

 

Answers (2)

As we learnt in

Gauss's Law -

Total flux linked with a closed surface called Gaussian surface.

Formula:

\phi = \oint \vec{E}\cdot d\vec{s}=\frac{Q_{enc}}{\epsilon _{0}}

 

- wherein

No need to be a real physical surface.

Qenc - charge enclosed by closed surface.

 

W= QV

\therefore \: \: \: V= \frac{W}{Q}= \frac{2}{20}= 0.1\: \: \: volt


Option 1)

0.1\: V

Correct

Option 2)

8\: V

Incorrect

Option 3)

2\: V

Incorrect

Option 4)

0.5\: V

Inocrrect

N neha

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