# On moving a charge of 20 coulomb by 2 cm, 2 J of work is done, then the potential difference between the points is Option 1) Option 2) Option 3) Option 4)

N neha
P Plabita

As we learnt in

Gauss's Law -

Total flux linked with a closed surface called Gaussian surface.

Formula:

$\dpi{100} \phi = \oint \vec{E}\cdot d\vec{s}=\frac{Q_{enc}}{\epsilon _{0}}$

- wherein

No need to be a real physical surface.

Qenc - charge enclosed by closed surface.

$W= QV$

$\therefore \: \: \: V= \frac{W}{Q}= \frac{2}{20}= 0.1\: \: \: volt$

Option 1)

Correct

Option 2)

Incorrect

Option 3)

Incorrect

Option 4)

Inocrrect

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