The total energy of the electron in the hydrogen atom in the ground state is -13.6 eV. Which of the following is its kinetic energy in the first excited state?

 

  • Option 1)

    13.6 eV

  • Option 2)

    6.8 eV

     

  • Option 3)

     3.4 eV

     

  • Option 4)

    1.825 eV

     

 

Answers (1)
V Vakul

 

Relation between K.E.,P.E. & total energy -

K.E.= \left ( Total\: energy \right )\\=\frac{1}{2}\left ( Potential \: energy \right )

- wherein

Potential Energy and total energy are negative .While kinetic energy is positive

 

 Total energy in first excited state = \dot-13.6 (\frac{1}{4}) =-3.4 ev

K.E=\left | total \ energy \right |=3.4 ev

 

 


Option 1)

13.6 eV

Incorrect option

Option 2)

6.8 eV

 

Incorrect option

Option 3)

 3.4 eV

 

correct option

Option 4)

1.825 eV

 

Incorrect option

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