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  • Solve it, There are two urns. Urn A has 3 distinct red balls and urn B has 9 distinct blue balls. From each urn two balls are taken out at random and then transferred to the other. The number of ways in which this can be done is

There are two urns. Urn A has 3 distinct red balls and urn B has 9 distinct blue balls. From each urn two balls are taken out at random and then transferred to the other. The number of ways in which this can be done is

  • Option 1)

    3

  • Option 2)

    36

  • Option 3)

    66

  • Option 4)

    108

 

Answers (1)

best_answer

As we learnt in

Theorem of Combination -

Each of the different groups or selection which can be made by taking r things from n things is called a combination.

^{n}c_{r}=\frac{(n)!}{r!(n-r)!}

- wherein

Where 1\leq r\leq n

 

 Urn A \rightarrow 3 Red balls.

Urn B \rightarrow 9 Blue balls

Number of ways =^{3}C_{2}\times^{9}C_{2}=\frac{3\times 9\times 8}{2}=108

Correct option is 4.

 


Option 1)

3

This is an incorrect option.

Option 2)

36

This is an incorrect option.

Option 3)

66

This is an incorrect option.

Option 4)

108

This is the correct option.

Posted by

Plabita

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