Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Solve it, Two straight long conductors AOB and COD are perpendicular to each other and carry currents i1 and i2. The magnitude of the magnetic induction at a point P at a distance a from the point O in a direction perpendicular to the plane ACBD is

Two straight long conductors AOB and COD are perpendicular to each other and carry currents i1 and i2. The magnitude of the magnetic induction at a point P at a distance a from the point O in a direction perpendicular to the plane ACBD is

  • Option 1)

    \frac{\mu 0\left ( i1+i2 \right )}{2\pi a}

  • Option 2)

    \frac{\mu 0\left ( i1-i2 \right )}{2\pi a}

  • Option 3)

    \frac{\mu 0\left ( (i1)^{2}+(i2)^{2} \right )^{\frac{1}{2}}}{2\pi a}

  • Option 4)

    \frac{\mu 0 i1 i2 }{\left ( l1+l2 \right )2\pi a}

 

Answers (1)

best_answer

As we learnt in 

For Infinite Length -

\phi_{1}=\phi_{2}=90^{\circ}

B=\frac{\mu_{o}}{4\pi}\:\frac{2i}{r}\:

- wherein

 

Magnetic field due to both AOB and COD are respectively :

B_{1}= \frac{\mu_{0}i_{1}}{2 \pi a}\:\:\:\:\: and\:\:\:\:\: B_{2}=\frac{\mu_{0}i_{2}}{2 \pi a}

B_{1} and B_{2} are perpendicular to each other.

\Rightarrow B= \sqrt {B^{2}_{1}+B^{2}_{2}}= \frac{\mu_{o}}{2 \pi a} \sqrt {i^{2}_{1}+i^{2}_{2}}


Option 1)

\frac{\mu 0\left ( i1+i2 \right )}{2\pi a}

This option is incorrect.

Option 2)

\frac{\mu 0\left ( i1-i2 \right )}{2\pi a}

This option is incorrect.

Option 3)

\frac{\mu 0\left ( (i1)^{2}+(i2)^{2} \right )^{\frac{1}{2}}}{2\pi a}

This option is correct.

Option 4)

\frac{\mu 0 i1 i2 }{\left ( l1+l2 \right )2\pi a}

This option is incorrect.

Posted by

Plabita

View full answer

Similar Questions

Trending Articles/News

anam-khan

BITSAT 2025 registration link active at bitsadmission.com; exam schedule, eligibility criteria
anam-khan

BITSAT 2025 registration begins today for 10 BE, 6 MSc, BPharm courses; eligibility, fee
anam-khan

BITSAT 2025 registration from tomorrow at bitsadmission.com; eligibility criteria

Latest Question