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  • Solve it, When the current changes from +2 A to –2 A in 0.05 second, an e.m.f. of 8 V is induced in a coil. The coefficient of self­induction of the coil is

When the current changes from +2 A to –2 A in 0.05 second, an e.m.f. of 8 V is induced in a coil. The coefficient of self­induction of the coil is

  • Option 1)

    0.2 H

  • Option 2)

    0.4 H

  • Option 3)

    0.8 H

  • Option 4)

    0.1 H

 

Answers (1)

best_answer

As we learnt in 

Self Inductance -

An emf is induced in the coil or the circuit which oppose the change that causes it. Which is also known back  emf.

- wherein

L=\frac{-e}{di/dt}=\frac{-8\times 0.05}{-4}=0.1 H


 


Option 1)

0.2 H

This option is incorrect

Option 2)

0.4 H

This option is incorrect

Option 3)

0.8 H

This option is incorrect

Option 4)

0.1 H

This option is correct

Posted by

Plabita

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