# Which among the following factors is the most important in making fluorine the strongest oxidising agent? Option 1) Electron affinity Option 2) Ionization energy Option 3) Hydration enthalpy Option 4) Bond dissociation energy

Answers (1)
S Sabhrant Ambastha

As we learnt in

Electron gain enthalpy -

When an electron is added to a neutral gaseous atom (x) to convert it into a negative ion, the enthalpy change accompanying the process is defined as the electron gain enthalpy
$(\Delta_{eg}H^\circleddash )$

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There are two factors that affect fluorine's oxidizing power namely Hydration enthalpy and Bond energy. But of these, Hydration enthalpy plays a greater role than the other.

Option 1)

Electron affinity

Incorrect

Option 2)

Ionization energy

Incorrect

Option 3)

Hydration enthalpy

Incorrect

Option 4)

Bond dissociation energy

Correct

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