Which one of the following pairs of species have the same bond order?

  • Option 1)

    NO^{+}\: and \: CN^{+}

  • Option 2)

    CN^{-}\: and \: NO^{+}

  • Option 3)

    CN^{-}and \: CN^{+}

  • Option 4)

    O{_{2}}^{-}and \: CN^{-}

 

Answers (2)

As learnt in

Bond Order -

Bond order is defined as one half the difference between the number of electrons present in the bonding and the antibonding orbitals.

- wherein

Bond \:Order=\frac{N_{b}-{N_{a}}}{2}

 

 

In the given pair of species number of electron in NO^{+} = number of electron in CN^{-}= 14 electrons.

So they are isoelectronic in nature. Hence bond order of these two species will be also similar which is shown below.

NO+ and CN- has same bond order..

 


Option 1)

NO^{+}\: and \: CN^{+}

This option is incorrect

Option 2)

CN^{-}\: and \: NO^{+}

This option is correct

Option 3)

CN^{-}and \: CN^{+}

This option is incorrect

Option 4)

O{_{2}}^{-}and \: CN^{-}

This option is incorrect

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