# Which one of the following pairs of species have the same bond order? Option 1) $NO^{+}\: and \: CN^{+}$ Option 2) $CN^{-}\: and \: NO^{+}$ Option 3) $CN^{-}and \: CN^{+}$ Option 4) $O{_{2}}^{-}and \: CN^{-}$

N neha
P Prateek Shrivastava

As learnt in

Bond Order -

Bond order is defined as one half the difference between the number of electrons present in the bonding and the antibonding orbitals.

- wherein

$Bond \:Order=\frac{N_{b}-{N_{a}}}{2}$

In the given pair of species number of electron in $NO^{+}$ = number of electron in $CN^{-}= 14$ electrons.

So they are isoelectronic in nature. Hence bond order of these two species will be also similar which is shown below.

NO+ and CN- has same bond order..

Option 1)

$NO^{+}\: and \: CN^{+}$

This option is incorrect

Option 2)

$CN^{-}\: and \: NO^{+}$

This option is correct

Option 3)

$CN^{-}and \: CN^{+}$

This option is incorrect

Option 4)

$O{_{2}}^{-}and \: CN^{-}$

This option is incorrect

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