A body of mass m  accelerates uniformly from rest   to \nu  in time T  The instantaneous power delivered to the body as a function of time is given by 

Option 1)

\frac{1}{2}\frac{m\nu ^{2}}{T^{2}}t

Option 2)

\frac{1}{2}\frac{m\nu ^{2}}{T^{2}}t^{2}

Option 3)

\frac{m\nu ^{2}}{T^{2}}\cdot t

Option 4)

\frac{m\nu ^{2}}{T^{2}}\cdot t^{2}

Answers (2)

As we learnt in

Power if the force is constant -

P=\frac{dw}{dt}= P= \vec{F}\cdot \vec{v}

- wherein

\vec{F}\rightarrow force

\vec{v}\rightarrow velocity

 

 Acceleration =\frac{v}{T}

at any time t, velocity v =(\frac{v}{T})t               ........(1)

Instantaneous power P = Fv

P=(ma).v

    =m(\frac{v}{T}).(\frac{v}{T})t

P=m\frac{v^{2}}{T^{2}}t

Correct answer is 3


Option 1)

\frac{1}{2}\frac{m\nu ^{2}}{T^{2}}t

This is an incorrect option.

Option 2)

\frac{1}{2}\frac{m\nu ^{2}}{T^{2}}t^{2}

This is an incorrect option.

Option 3)

\frac{m\nu ^{2}}{T^{2}}\cdot t

This is the correct option.

Option 4)

\frac{m\nu ^{2}}{T^{2}}\cdot t^{2}

This is an incorrect option.

N neha

Preparation Products

Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Test Series JEE Main April 2021

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 6999/- ₹ 4999/-
Buy Now
JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Test Series JEE Main April 2022

Take chapter-wise, subject-wise and Complete syllabus mock tests and get an in-depth analysis of your test..

₹ 6999/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
 
Exams
Articles
Questions