If the system of linear equations
x + y + z = 5
x + 2y + 2z = 6
x + 3y + z =
, (
,
) , has infinitely
many solutions, then the value of +
is :
12
9
7
10
x + 3y + z -
= p ( x + y + z - 5) + q ( x + 2y + 2z - 6 )
On comparing the coefficients
p + q = 1 and p + 2q = 3
=> ( p , q ) = ( -1 , 2 )
Hence, x + 3y + z -
= x + 3y + 3z - 7
=>
=>
So, option (4) is correct.
Option 1)
12
Option 2)
9
Option 3)
7
Option 4)
10
Study 40% syllabus and score up to 100% marks in JEE