If the system of linear equations
x + y + z = 5
x + 2y + 2z = 6
x + 3y + z = , (, ) , has infinitely
many solutions, then the value of + is :
12
9
7
10
x + 3y + z - = p ( x + y + z - 5) + q ( x + 2y + 2z - 6 )
On comparing the coefficients
p + q = 1 and p + 2q = 3
=> ( p , q ) = ( -1 , 2 )
Hence, x + 3y + z - = x + 3y + 3z - 7
=>
=>
So, option (4) is correct.
Option 1)
12
Option 2)
9
Option 3)
7
Option 4)
10
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