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 Some energy levels of a molecule are shown in the figure.  The ratio of the wavelengths r=λ12, is given by :

  • Option 1)

    r= \frac{4}{3}

  • Option 2)

    r= \frac{2}{3}

  • Option 3)

    r= \frac{3}{4}

  • Option 4)

    r= \frac{1}{3}

 

Answers (1)

best_answer

As we learnt in

Energy emitted due to transition of electron -

\Delta E= Rhcz^{2}\left ( \frac{1}{n_{f}\, ^{2}}-\frac{1}{n_{i}\, ^{2}} \right )

\frac{1}{\lambda }= Rz^{2}\left ( \frac{-1}{n_{i}\, ^{2}}+\frac{1}{n_{f}\, ^{2}} \right )

- wherein

R= R hydberg\: constant

n_{i}= initial state \\n_{f}= final \: state

 

 From the figure.

\lambda_{1}=\frac{hc}{\Delta E_{1}}=\frac{hc}{-E-(-2t)}=\frac{hc}{E}

\lambda_{2}=\frac{hc}{-E-\left(-\frac{4E}{3} \right )}-\frac{hc}{(\frac{E}{3})}.3\frac{hc}{E}

\frac{\lambda_1}{\lambda_2}=\frac{1}{3}

Correct option is 4


Option 1)

r= \frac{4}{3}

This is an incorrect option.

Option 2)

r= \frac{2}{3}

This is an incorrect option.

Option 3)

r= \frac{3}{4}

This is an incorrect option.

Option 4)

r= \frac{1}{3}

This is the correct option.

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perimeter

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