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The acce;eration of a particle performing SHM is 12\; cm/s^{2} at a distace of 3 cm from the mean position. Its time period is 

  • Option 1)

    0.5\; s

  • Option 2)

    1.0\; s

  • Option 3)

    2.0\; s

  • Option 4)

    3.14\; s

 

Answers (1)

T = 2\pi\sqrt{\frac{Displacement}{Acceleration}} = 2\pi\sqrt{\frac{3}{12}} = \pi=3.14s

 

Equation of S.H.M. -

a=-\frac{d^{2}x}{dt^{2}}= -w^{2}x

w= \sqrt{\frac{k}{m}}

 

- wherein

x= A\sin \left ( wt+\delta \right )

 

 

 


Option 1)

0.5\; s

This is incorrect.

Option 2)

1.0\; s

This is incorrect.

Option 3)

2.0\; s

This is incorrect.

Option 4)

3.14\; s

This is correct.

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subam

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