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Solve! - Physical and Chemical Equilibria - BITSAT-3

The mass of AgNo_{3} present in 100 ml of its 0.25 Molar solution is

  • Option 1)

    4.25 g

  • Option 2)

    42.5 g

  • Option 3)

    17g

  • Option 4)

    1.7 g

 
Answers (1)
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As learnt in

Molarity -

Molarity = \frac{Moles \: of \: solute}{V\! ol.of\: solution(L)}

-

 

 moles of AgNO_{3} in 100ml = 0.25\times 10^{-1} 

                                 = 0.025

mass = 0.025\times 170g=4.25g

 


Option 1)

4.25 g

This solution is correct

Option 2)

42.5 g

This solution is incorrect

Option 3)

17g

This solution is incorrect

Option 4)

1.7 g

This solution is incorrect

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