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Amount of oxalic acid present in a solution can be determined by its titration with KMnO_{4} solution in the presence of H_{2}SO_{4}. The titration gives unsatisfactory result when carried out in the presence of  HCl, because HCl

  • Option 1)

    oxidises oxalic acid to carbon dioxide and water

  • Option 2)

    gets oxidised by oxalic acid to chlorine

  • Option 3)

    Furnishes H^{+} ions in addition to those from oxalic acid

  • Option 4)

    reduces permanganate to Mn^{2+}

 

Answers (1)

best_answer

As we learnt in

Standard Electrode Potential Value -

-

 

 

Oxalic acid present in a solution can be determined by its titration with KMnO_{4} solution in the presence of H_{2}SO_{4}

Titration cannot be done in the presence of HCl becauseKMnO_{4} being a strong oxidizing agent oxidises HCl\: to\: Cl_{2}  and get itself reduced to Mn^{2+} So actual amount of oxalic acid in solution can­ not be determined.


Option 1)

oxidises oxalic acid to carbon dioxide and water

This option is incorrect.

Option 2)

gets oxidised by oxalic acid to chlorine

This option is incorrect.

Option 3)

Furnishes H^{+} ions in addition to those from oxalic acid

This option is incorrect.

Option 4)

reduces permanganate to Mn^{2+}

This option is correct.

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prateek

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