# Amount of oxalic acid present in a solution can be determined by its titration with $\dpi{100} KMnO_{4}$ solution in the presence of $\dpi{100} H_{2}SO_{4}$. The titration gives unsatisfactory result when carried out in the presence of  $\dpi{100} HCl$, because $\dpi{100} HCl$ Option 1) oxidises oxalic acid to carbon dioxide and water Option 2) gets oxidised by oxalic acid to chlorine Option 3) Furnishes $H^{+}$ ions in addition to those from oxalic acid Option 4) reduces permanganate to $Mn^{2+}$

P Prateek Shrivastava

As we learnt in

Standard Electrode Potential Value -

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Oxalic acid present in a solution can be determined by its titration with $KMnO_{4}$ solution in the presence of $H_{2}SO_{4}$

Titration cannot be done in the presence of $HCl$ because$KMnO_{4}$ being a strong oxidizing agent oxidises $HCl\: to\: Cl_{2}$  and get itself reduced to $Mn^{2+}$ So actual amount of oxalic acid in solution can­ not be determined.

Option 1)

oxidises oxalic acid to carbon dioxide and water

This option is incorrect.

Option 2)

gets oxidised by oxalic acid to chlorine

This option is incorrect.

Option 3)

Furnishes $H^{+}$ ions in addition to those from oxalic acid

This option is incorrect.

Option 4)

reduces permanganate to $Mn^{2+}$

This option is correct.

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