Q

Solve! - Surface Chemistry - JEE Main

A gas undergoes physical adsorption on a surface and follows the given Freundlich

$\frac{x}{m}=kp^{0.5}$

Adsorption of the gas increases with:

• Option 1)

Decrease in p and increase in T

• Option 2)

Decrease in p and decrease in T

• Option 3)

Increase in p and decrease in T

• Option 4)

Increase in p and increase in T

Views

$\frac{x}{m}=kp^{0.5}$

$=>$ Adsorption capacity $(\frac{x}{m})$ increases with increase in Pressure.

Now; Physisorption ( Physical adsorption ) is always an exothermic process.

$\therefore$ Adsorption decreases with increase in temperature.

$\therefore$ option (3) is correct.

Option 1)

Decrease in p and increase in T

Option 2)

Decrease in p and decrease in T

Option 3)

Increase in p and decrease in T

Option 4)

Increase in p and increase in T

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