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The radius of the first Bohr orbit is ao. The nth orbit has a radius:

  • Option 1)

    nao

     

  • Option 2)

     ao/n
     

  • Option 3)

     n2ao
     

  • Option 4)

    ao/n2

 

Answers (1)

best_answer

 

Radius of nth orbital -

r_{n}= \frac{\epsilon _{0}n^{2}h^{2}}{\pi mZe^{2}}

 

- wherein

r_{n}\alpha \: \frac{n^{2}}{Z}

\frac{\epsilon_{0}h^{2}}{\pi me^{2}}= 0.529A^{\circ}

 

 r=\frac{n^{2}}{z} a_{0}

For z=1, r=n^{2}a_{0}


Option 1)

nao

 

This solution is incorrect.

Option 2)

 ao/n
 

This solution is incorrect.

Option 3)

 n2ao
 

This solution is correct.

Option 4)

ao/n2

This solution is incorrect.

Posted by

divya.saini

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