The radius of the first Bohr orbit is ao. The nth orbit has a radius: Option 1) nao   Option 2)  ao/n   Option 3)  n2ao   Option 4) ao/n2

Answers (1)

Radius of nth orbital -

$r_{n}= \frac{\epsilon _{0}n^{2}h^{2}}{\pi mZe^{2}}$

- wherein

$r_{n}\alpha \: \frac{n^{2}}{Z}$

$\frac{\epsilon_{0}h^{2}}{\pi me^{2}}= 0.529A^{\circ}$

$r=\frac{n^{2}}{z} a_{0}$

For $z=1, r=n^{2}a_{0}$

Option 1)

nao

This solution is incorrect.

Option 2)

ao/n

This solution is incorrect.

Option 3)

n2ao

This solution is correct.

Option 4)

ao/n2

This solution is incorrect.

Preparation Products

Knockout BITSAT 2020

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 1999/-
Buy Now
Knockout BITSAT 2021

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 2999/-
Buy Now
Knockout BITSAT-JEE Main 2021

An exhaustive E-learning program for the complete preparation of JEE Main and Bitsat.

₹ 27999/- ₹ 16999/-
Buy Now
Knockout BITSAT-JEE Main 2020

An exhaustive E-learning program for the complete preparation of JEE Main and Bitsat.

₹ 14999/- ₹ 7999/-
Buy Now
Exams
Articles
Questions