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  • Solve this problem A heater of 220 V heats a volume of water in 5 minute time. A heater of 110 V heats the same volume of water in

A heater of 220 V heats a volume of water in 5 minute time. A heater of 110 V heats the same volume of water in

  • Option 1)

    5 minutes

  • Option 2)

    8 minutes

  • Option 3)

    10 minutes

  • Option 4)

    20 minutes

 

Answers (1)

best_answer

As we learnt in

Power dissipiated in external resistance -

P=(\frac{E}{R+r})^{2}R

-

 

 P=\frac{V^{2}}{R}

Energy = P . t

Initial energy = Final energy 

P_{1}t_{1}=P_{2}t_{2}\Rightarrow t_{2}=\frac{P_{1}}{P_{2}}t_{1}

t_{2}=(\frac{v_{2}}{v_{1}})^{2}.t_{1} = 20 minutes

 


Option 1)

5 minutes

Incorrect Option

Option 2)

8 minutes

Incorrect Option

Option 3)

10 minutes

Incorrect Option

Option 4)

20 minutes

Correct Option

Posted by

Plabita

View full answer

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